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from math import *
sum = 0
list = [3+n for n in range (100000) if n%2 == 0]
prime = 2
count = 1

for i in range(0,100000):
    if count == 1000:
        print '1000th prime number is ', prime
        print 'The ratio is ', (sum/prime)
        break
    else:
        test = list[i]
        for o in range (0,i+1):
            divtest = list[o]
            if test%divtest == 0 and o == i:
                sum += log(prime)
                prime = test
                count +=1
                
            elif test%divtest == 0 and o!= i:
                break

Pasted: May 24, 2011, 3:10:01 am
Views: 12